Anyone here a math genius?

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Anyone here a math genius?

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01-22-2011, 12:46 PM

Trip

Hold mah beer!

Join Date: Feb 2008

Location: 80 Miles South of Moto Heaven

Moto: 08 R1200GS

Posts: 23,268

This is what I got

y^x=3y-1

x= (ln(3y-1)/ln(y)) only if y > 1/3

z=3^x+5

z = (3y-1)^(ln(3)/ln(y))+5

So basically we have two equations and 3 unknowns.

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