01-22-2011, 10:46 AM | #1 |
Let's do another U-turn
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Anyone here a math genius?
A friend on facebook posted this problem from her son's 6th grade math. I'm clearly an idiot, cause I can't figure it out.
If y*=3y-1, then what is 3*+5? Seems to me that you have to solve for the y and also for the exponent, but I can't figure out how. |
01-22-2011, 10:58 AM | #2 |
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What does the "*" represent? Never mind I get it... you think you're dumb! Hahahaha
Last edited by Amber Lamps; 01-22-2011 at 11:18 AM.. |
01-22-2011, 12:10 PM | #3 |
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Is y* supposed to be y^x where x is a variable?
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01-22-2011, 12:13 PM | #4 | |
Hold mah beer!
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yeah what was said above, the way you got it typed doesn't make sense and it's like his teacher made shit up. * is generally thought of as multiplication.
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01-22-2011, 12:18 PM | #5 |
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01-22-2011, 12:21 PM | #6 | ||
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Quote:
Quote:
If y^x = 3y-1, then what is (3^x) + 5? |
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01-22-2011, 12:28 PM | #7 |
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I dont think that was copied right, if solve for x you get a complex number.
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01-22-2011, 12:29 PM | #8 |
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01-22-2011, 12:38 PM | #9 | |
Hold mah beer!
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yep, there is some math in there that is not 6th grade level, i think there is some missing info that the teacher gave. I don't remember logarithms that early.
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01-22-2011, 12:38 PM | #10 |
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I put it in Wolfram Alpha to see if I was missing something.
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