01-22-2011, 01:46 PM | #11 | |
Hold mah beer!
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This is what I got
y^x=3y-1 x= (ln(3y-1)/ln(y)) only if y > 1/3 z=3^x+5 z = (3y-1)^(ln(3)/ln(y))+5 So basically we have two equations and 3 unknowns.
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01-22-2011, 01:46 PM | #12 |
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01-22-2011, 01:49 PM | #13 | |
Hold mah beer!
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because without more info there is infinite solutions.
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01-22-2011, 01:53 PM | #14 |
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Well the fact that we start with two variables, and only one complete equation means that you cant solve for both variables.
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01-22-2011, 02:00 PM | #15 |
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01-22-2011, 02:48 PM | #16 |
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Every now and again I like to look in these threads to make myself feel dumb. Success.
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01-22-2011, 02:51 PM | #17 |
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01-22-2011, 02:54 PM | #18 | |
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01-22-2011, 03:23 PM | #19 |
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Sounds like you need to get more info from her before any of us can solve it.
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01-22-2011, 03:26 PM | #20 |
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